Two charges are fixed in place on the x-axis as shown. The charge at x = 0 is negative and has magnitude q = 2 mCoulombs. The charge at x = d, (d = +12 cm), is positive and has magnitude Q = 4 mCoulombs. Find a point x = xo along the x-axis at which the electric field is zero.
https://tycho-s.phys.washington.edu/cgi/鈥?/a>
Xo= ?cm|||Edit***
q1 = -2 * 10 ^ -3 'C
q2 = 4 * 10 ^ -3 'C
k = 9 * 10 ^ 9
12 centimeters = 0.12 meters
E1 = k * q1 / (x) ^ 2
E2 = k * q2 / (x+0.12) ^ 2
solving for x:
x = 0.12 / (Sqr(q2 / |q1|) - 1)
x =0.2897 m "Left of origin"
x = 28.97 cm
check:
E1 = -214466094 N/C
E2 = 214466094 N/C
鈭慐=0
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